How to run php script in shell

good tutorial more power to you

Great simple basic tutorial. Thanks…

And what if hello.php contains the following?

#!/usr/bin/php

How do I call hello.php with argument msg=hello+world?
The following doesn’t work:

php hello.php?msg=hello+world

Ooops, the php tag are interpreted!
And what if hello.php contains the following?
#!/usr/bin/php
<?php
echo $_GET[msg];
?>
How do I call hello.php with argument msg=hello+world?
The following doesn’t work:
php hello.php?msg=hello+world

How would you do this with cmd in windows.

@santiago: I know it is kind of strange to expect to GET Parameters.. but I am searching for the same as I would like to implement a cronjob that would need some input-variable.

I tried as vector:
./hello.php -msg hello

to no avail..

ok .. solution:
echo>./hello.php vector1

and catch it in PHP with

echo($argv[1]);

Caution!: on index 0 you woulg get “./hello.php”

Hi expert,

How can run bellow line using bash script
http://10.1.4.8/corp_bulk.php?user=xyz&pass=123&ms=test&text=test

Thanks in advance.

Faruk

thanks! that was very helpful.
I did at some point know this stuff, but I needed to know it again tonight, and now I do!
:)

When I run ‘which php’….It shows me result as below
/usr/bin/php

I added the following line to my script
#!/usr/bin/php

But when I execute the script like ‘./script.php’, it shows me error as below.
-bash: ./script.php: /usr/bin/php^M: bad interpreter: No such file or directory

Please suggest what could be wrong here?

Thanks in advance …

Hey Rahul VK Khandelwal,

Your file might be in the wrong format. DOS format (newline is \r\n) instead of unix format (newline is \n).
Good luck

Santiago

Thanks a ton Santiago. I changed the format with dos2unix and it worked for me.

Thanks!